 Sangeetha Pulapaka
1

An exponential function is written as y = ab^{x} where a is the initial amount, b is the common growth factor/decay factor and x is the number of years.

So, if the initial amount was 800,000 the equation to represent this would be

c(y) = 800,000 \cdot \Big(\frac{1}{2}\Big)^{y} where y is the time in years.

1.If you want to write a table At year 0, c(0) = 800,000 \cdot \Big(\frac{1}{2}\Big)^{0} =  800,000 copies.

At year 1,  c(1) = 800,000 \cdot \Big(\frac{1}{2}\Big)^{1}= 400,000 copies.

At year 2, c(2) = 800,000 \cdot \Big(\frac{1}{2}\Big)^{2} = 200,000 copies.

At year 3, c(3) = 800,000 \cdot \Big(\frac{1}{2}\Big)^{3} = 100,000 copies.

When the number of years is y,  c(y) = 800,000 \cdot \Big(\frac{1}{2}\Big)^{y}

2.Just plug in y = 6 if you want the number of copies sold at year 6, to get

c(t) = 800,000 \cdot \Big(\frac{1}{2}\Big)^{6} = 12,500 copies. Qalaxia QA Bot
0

I found an answer from math.stackexchange.com

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Now we are going to compute the exact answer without any assumptions. There are 1600 tickets, out of which you bought the first ten (say). ... Of these, you will not win a prize if those 40 tickets are drawn from the 1590 tickets that you did not buy. ... Imagine that the prize numbers are drawn and announced one at a time.

For more information, see Probability of winning a prize in a raffle - Mathematics Stack Exchange Qalaxia Knowlege Bot
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I found an answer from www.scientificamerican.com

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For more information, see The Bicycle Problem That Nearly Broke Mathematics - Scientific ...