Krishna
0

Step 1:  Make a note of the given vertices

Given: A(-4, 0), B(4, 0) and C(0, 3)

Step 2:  Find the distance between the points

The distance between points A(-4, 0), B(4, 0)

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = $\sqrt{[4 -(-4)]^2 + (0 - 0)^2}$

AB = \sqrt{64}

AB = 8

The distance between points B(4, 0), C(0, 3)

BC = \sqrt{(0 - 4)^2 + (3 - 0)^2}

BC = \sqrt{16 + 9}

BC = \sqrt{25}

BC = 5

The distance between points C(0, 3), A(-4, 0),

CA = \sqrt{(-4 - 0)^2 + (0 - 3)^2}

CA = \sqrt{16 + 9}

CA = \sqrt{25}

CA = 5

BC = CA = 5

Two sides of the triangle are equal

Hence, we can conclude that the given vertices are the vertices of the isosceles triangle