Krishna
0

Step 1:  Make a note of the given vertices

              Given: A(-4, 0), B(4, 0) and C(0, 3)


Step 2:  Find the distance between the points

                The distance between points A(-4, 0), B(4, 0)  

                    AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

                    AB = [math] \sqrt{[4 -(-4)]^2 + (0 - 0)^2} [/math]

                    AB = \sqrt{64}

                    AB = 8

              The distance between points B(4, 0), C(0, 3)  

                    BC = \sqrt{(0 - 4)^2 + (3 - 0)^2}

                    BC = \sqrt{16 + 9}

                    BC = \sqrt{25}

                    BC = 5

            The distance between points C(0, 3), A(-4, 0),

                    CA = \sqrt{(-4 - 0)^2 + (0 - 3)^2}

                    CA = \sqrt{16 + 9}

                    CA = \sqrt{25}

                    CA = 5  


          BC = CA = 5

         Two sides of the triangle are equal

    Hence, we can conclude that the given vertices are the vertices of the isosceles triangle