The points Q (1, 3) and R (7, 0) lie on the line l_1, as shown in the diagram above.

The line l_2 is perpendicular to l_1, passes through Q and crosses the y-axis at the point P(0, 1) , as shown in the diagram above.
i) Find the area of âPQR.
The line l_2 is perpendicular to l_1, passes through Q and crosses the y-axis at the point P(0, 1) , as shown in the diagram above.
i) Find the area of âPQR.
Method 1:
Step 1: Locate the coordinates of the endpoints.
EXAMPLE: The given points M (2, 3) and N (-1, 0), (2, -4.)
Therefore, (x_1, y_1) = (2, 3),(x_2, y_2) = (-1, 0) and (x_3, y_3) = (2, -4).
Step 2: Plug the corresponding coordinates into the Area of triangle formula
FORMULA:
Area of the triangle
\frac{1}{2} {x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)}
Step 3: Simplify further
NOTE: Apply the BODMAS rules
Method 2:
Step 1: Calculate the base and height lengths of the triangle
NOTE: Use the distance formula to calculate lengths.
Step 2: Substitute the either values (base and height lengths) in the formula
Area of the right angle triangle = \frac{1}{2} base * height
Step 3: Simplify further
NOTE: Apply the BODMAS rules