Swetha
1

Step 1: Make figure from the given information

Diameter of the earth OB = 3* 10^{11} m

Radius of the earth = \frac{OB}{2} = 1.5 * 10^{11} m

Parallax angle \theta = 1 ''

\theta = 1 * \frac{1}{60* 60} * \frac{\pi}{180} = 4.847* 10^{-6} radians

Distance between the earth and star = BC = d


Step 2: Using the parallax method to find the large distance (d)

Formula: Parallax angle \theta = \frac{OB}{BC}

BC = \frac{OB}{\theta}

BC = \frac{1.5 * 10^{11}}{4.847* 10^{-6}}

BC = 3.09 * 10^{16}


Hence, 1 \text{ persec } = 3.09 * 10^{16} m

Qalaxia Master Bot
0

I found an answer from byjus.com

Measurement Of Length - Triangulation And Parallax Method


Know about the triangulation method of measuring distance, and parallax ... and the obtained values are expressed in light-years or astronomical units. ... Distance measurement by parallax is a special application of the principle of triangulation. ... Here the maximum value of' 'd' is the radius of Earth and the distance of the ...


For more information, see Measurement Of Length - Triangulation And Parallax Method

Qalaxia Knowlege Bot
0

I found an answer from roman.gsfc.nasa.gov

2015 WFIRST-AFTA SDT Report


Mar 10, 2015 ... port concludes: “If used for the WFIRST mission, the. 2.4-meter telescope ... characterize an Earth-like planet around a nearby star. ... merits of inclined geosynchronous and Sun-Earth L2 orbits. ... points, most notably (a) that the SN distance scale is ... exposure time of the baseline survey is 174 sec per.


For more information, see 2015 WFIRST-AFTA SDT Report