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Fitting a line to data (video) | Khan Academy

Sal creates a scatter plot and then fits a line to data on the median California family income.

For more information, see Fitting a line to data (video) | Khan Academy

I found an answer from byjus.com

**Errors** in **Measurement** - Absolute **Error**, **Relative Error** and ...

Learn about the **Errors** in **Measurement** in a detailed manner with the concepts of
Absolute **Error**, **Relative Error**, **Percentage Error** and Tolerance at BYJU'S.

For more information, see **Errors** in **Measurement** - Absolute **Error**, **Relative Error** and ...

I found an answer from web.stanford.edu

Problem Solutions

**Calculate** the free energy of the aluminum/oxygen reaction. Here are the ... The
internal **resistance** of the cell is **R** = 0.001 Ω, and the total resis- ... Page 1 of **5**.
257 ... WIC = **0.2** × 21.1=4.2 ... The ideal methanol fuel cell delivers 1.175 **V** when
air is used. ... To keep the pressure reading **error** within **10**% (**10** × 105 at 1 MPa),
.

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How to **find the percentage error** in the equivalent **resistance** when ...

So,**for resistance** 6 & **10** ohm the equivalent **resistance** => 1/**R**=(1/6)+(1/**10**) ... So
the % **error** in the measurements as {(3.6038–3.75)/3.75}×**100**% and ... A 3.0 **V**
battery has an internal **resistance** of 0.5 ohms and is connected to a load ... The
values of two resistors are (5.0+**0.2**) and (10.0+0.1). ... R1 is **5** ohms, R2 is 12
ohms.

For more information, see How to **find the percentage error** in the equivalent **resistance** when ...

If two quantities are multiplied or divided, the result's relative error is equal to the sum of the multipliers' relative errors.

\frac{\Delta Z}{Z} = \frac{\Delta A}{A} + \frac{\Delta B}{B}

Given that

Resistance R = \frac{V}{I}

Voltage V = (100 \pm 5) V

Current I = (10 \pm 0.2) A

Step 1: Identify the percentage error in R = ?

Error in voltage \Delta V = 5 %

Error in current \Delta I = 0.2 %

Error in \frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}

\frac{\Delta R}{R} = \frac{5}{100} + \frac{0.2}{10}

\frac{\Delta R}{R} = 5% + 2% = 7%

Hence, percentage error in resistance = 7%