#### The straight line l_2 passes through the origin and has gradient –4. (b) Write down an equation for l_2.

Anonymous

0

Anonymous

0

Krishna

0

Step 1: Substitute either values slope(m) and any one point into the equation of a straight line.

NOTE: Take the point as (0, 0)

FORMULA: Equation of a straight line

y - y_1 = m(x - x_1)

Where m = slope and ( x_1, y_1) = any point

EXAMPLE: I took (2, 0) as a point and m = \frac{4}{5}

y - 0 = \frac{4}{5} ( x - 2)

5y = 4x - 8

Step 2: Simplify and make the equation in the form of Ax + By + C = 0