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Structure of atom | Class 11 Chemistry (India) | Science | Khan ...

We will learn the **dual nature** of **light** and electron, **quantum** mechanics, **quantum**
numbers. ... Particle **nature** of electromagnetic **radiation**: Planck's **quantum theory**
... To explain the **photoelectric effect**, 19th-century **physicists** theorized that the
oscillating ... The **energy** of a **photon** could be calculated using Planck's **equation**:
.

For more information, see Structure of atom | Class 11 Chemistry (India) | Science | Khan ...

Given that

Metals work function

Na: 2.75 eV, K : 2.30 eV, M_o : 4.17 eV, N_i : 5.15 eV

Wavelength \lambda = 3300 A^{^o} = 3300 * 10^{-10} m

Distance between the laser and photocell = 1 m

Step 1: Calculating the photoelectric emission of the radiation

Energy of proton E=h\upsilon\ =\ \frac{hc}{\lambda}

Where, h - Planck's constant([math] 6.63), speed of light c = 3*10^{8} m/s and \upsilon - frequency.

E = \frac{6.63 * 10^{-34} * 3 * 10^8}{3300 * 10^{-10} }

E = 6 * 10^{-19} joules

E = 3.76 eV \because 1 eV = 1.6* 10^{-19} J

Hence, photoelectric emission of the radiation E = 3.76 eV

Step 2: Metals under photoelectric emission Identification

The photon energy can be passed to the electron if the photon energy is at least as large as the work function.

Na and K:

Work function \phi < E photon energy.

So, photo electric emission is possible

M_o and N_i :

Work function \phi>E photon energy.

So, photo electric emission is not possible

Step 3: Intensity of radiation effect

The intensity of the radiation increases since the laser bought closer to the photocell (50 cm). But photon

energy does not depend on the intensity of the light.

Thus, the energy of incident radiation remains unchanged with a decrease in distance.