We drop this 0.1 kg apple 1 m. What speed does it hit the ground with?

The relation between kinetic and potential energy
The potential energy is the energy accumulated in an object by its location.
PE = mgh where, m - mass, g - acceleration due to gravity and h - height
The energy possessed by an object as a result of its motion is known as kinetic energy.
KE KE = \frac{1}{2} mv^2 Where, m-mass and v- velocity
Energy cannot be destroyed, only converted from one form to another, according to the law of conservation of energy.
PE begins from 0 at the projection point and increases to a maximum value at a constant speed at maximum height.
KE begins at the projection point with a maximum value and decrease constantly to 0 at maximum height.
Total energy = PE + KE.
At the maximum height (when object dropped): PE = KE
Given that
Mass of an apple m = 0.1 kg
Height h = 1 m
Acceleration due to gravity g = 9.8 m/s^2
Step 1: Set up an equation for the speed of the object
When an object is dropped, all of its potential energy transformed into kinetic energy.
PE = KE
mgh = \frac{1}{2} mv^2
v^2 = \frac{2mgh}{m}
v = \sqrt{2gh}
Step 2: Determining the speed of the object
v = \sqrt{2* 9.8* 1}
v = \sqrt{19.6} = 4.42
v = 4.42
Thus, the speed of the object v = 4.42 m/s