What is the angle of elevation of the top of a tree 12.7 m from a point 23.7 m away on level ground?

Step 1: Read the question and make a note of the important points
NOTE: Angle of elevation is the angle between observer's eye(horizontal
line of reference) and top of object at observer's line of sight (tree in this case).
Height of tree = y = 12.7 m
Horizontal Distance between point of observation and object= x = 23.7 m
Angle of elevation = \theta = ?
Step 2: Find the suitable trigonometric ratio to calculate angle of elevation
NOTE: Consider a right angled triangle formed with vertical side as height
of tree (y) and horizontal side as observation distance (x). Angle θ is the
acute angle formed which can be found using trigonometric function i.e.
\tan \theta .
Solution:
\tan \theta = \frac{opposite}{adjacent}
\tan \theta = \frac{y}{x}
\tan \theta = \frac{12.7}{23.7}
\tan \theta = 0.5358
\theta = \tan^{-1}(0.5358)
\theta = 28.1824
Therefore angle of elevation = \theta = 28.1824