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A 1000 **kg car** is **traveling** at 20 m/**s**. How much **kinetic energy** does it

Here, Given- mass=1000kg Speed=20m/**s** Formula for Ek=1/2mv² Putting the
value in the formula We get Ek=1/2×1000×20 =10000joules.

For more information, see A 1000 **kg car** is **traveling** at 20 m/**s**. How much **kinetic energy** does it

The kinetic energy is given by the formula

K.E = \frac{1}{2} m v^{2}

Plug in the value of mass m = 1500 and v=25 in this to get

K.E = \frac{1}{2} \times 1500 \times 25 \times 25

= 468,750 J

1 KJ = 1000 J

So, dividing the above value by 1000 , we get

= 468.750 KJ

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**what is the kinetic energy of a 1500 kg car traveling** at a speed of 30 ...

As for the height, set **kinetic** = potential **energy**. ... t = sqrt(110ft/32ft/**s**^2) t = a
million.86s I have not any concept the form to procure 0.33**s**.

For more information, see **what is the kinetic energy of a 1500 kg car traveling** at a speed of 30 ...

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A **1,500**-**kg car** is **moving** at a speed of 10 m/**s**. What is the **car's** ...

need to use the formula, **Kinetic energy** = 1/2 x mass (**kg**) x velocity^2 (m/**s**) **KE** =
1/2 x **1500** x 10^2. **KE** = 75000 Joules.

For more information, see A **1,500**-**kg car** is **moving** at a speed of 10 m/**s**. What is the **car's** ...

I found an answer from www.quora.com

A **car** of mass **1500 kg** accelerates from rest at 5 m/s2 for 5 **s** on a ...

A **car** of mass **1500 kg** accelerates from rest at 5 m/s2 for 5 s on a straight road. ....
I think I'd work out its **kinetic energy** at 25 metres/sec (it's velocity after 5 seconds)
in .... V= Vo + a t = 5 5 = **25 m**/**s** so E= 1/2 1500 25^2 = 468.750 Joules .... What
power is needed to sustain the motion of the mass of 5 kg body **moving** at a ...

For more information, see A **car** of mass **1500 kg** accelerates from rest at 5 m/s2 for 5 **s** on a ...

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Physics motion problem? | Yahoo Answers

... of problems are solved by matching the **kinetic energy** of the **moving** ... Energy
stored by the spring = 1/2(spring constant)(compressed ... of the situation, you
have a mid size **car** going at 55 mph (**25m**/**s**). ... **KE** of **car** = 1/2mV² = (0.5)(**1500**)(
25)² = 468,750 J ... A puck has a mass of 0.112 **kg** and is at rest.

For more information, see Physics motion problem? | Yahoo Answers

I found an answer from www.grc.nasa.gov

1st&2nd Laws of Motion

So any force that causes a body to **move** is an unbalanced force. ... If the units of
force are in newtons, then the units of mass are kilograms and the units of
acceleration are m/**s**^{2}. ... A force of 5000 newtons is applied to a 1200 kg **car** at
rest. ... What will be the acceleration when the truck has an additional load of
**1500 kg** ?

For more information, see 1st&2nd Laws of Motion