Raji
1

.. .. .. .. ..O.. .. ..O

.. ... .. .. .||.. .. .. ||

CH3-CH2-C-CH2-C-H

notice you have two functional groups? the ketone and the aldehyde? so the real question is which one takes precedence and how do you name the other?

here's a link with a table of precedence for organic nomenclature

http://en.wikipedia.org/wiki/Organic_nom...

3/4 of the way to the bottom of the page.

notice aldehydes is 4 while ketones is 5? aldehydes take precedence.

since this..

.. ... . .. ... ... ..... ..O

.. ... .. .. ...... . .. .. ||

CH3-CH2-CH2-CH2-C-H

is pentanal and this group

.. .O

.. .||

R-C-R'

is the "oxo".. when it doesn't have priority.. this..

.. .. .. . ..O.. .. ..O

.. ... .. .. .||.. .. .. ||

CH3-CH2-C-CH2-C-H

5... ..4.. ..3..2.. ..1

is 3-oxopentanal

************ *********

this...

.. .. .CH2-OH

... .. .|

CH3-CH-CH2-CH-CH3

.. .. .. . . . . . . |

.. .. .. .. . ... . .CH2-CH3

is clearly an alcohol. the real question is where is the longest straight chain and how do you deal with OH groups on a branch? Well if you can, the longest chain needs to contain the functional group. like this

.. .. .CH2-OH

... .. .|

.. ...-CH-CH2-CH-

.. .. .. . . . . . . |

.. .. .. .. . ... . .CH2-CH3

so if we redraw that compound with the longest straight chain..

.. .. .CH3.. .. ... .. CH3

... .. .|... .. .. .. .. .|

HO-CH3-CH-CH2-CH-CH2-CH3

... . 1.. .. 2.. .3.. ..4.. .5.. ..6

you can easily see this is ---> 1,4-dimethylhexan-1-ol.