STEP 1: Recall how to find the slope from the points given

http://cls.syr.edu/mathtuneup/grapha/Unit4/Unit4a.html

Locating (0,8) and (-2,0) we find the slope of the line

slope of the line is \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\frac{0-8}{-2-0}

=\frac{-8}{-2}

= 4

STEP 2: Recall on how to find the y-intercept

https://www.qalaxia.com/viewDiscussion?messageId=5a9ec87f9745ed386adeaff3

Locate the y-intercept on the graph.

The y-intercept is where the line touches the y-axis and the value of x is 0.

So, the y-intercept is 8

STEP 3: Recall the standard equation of a line

http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-strtlines-2009-1.pdf

The standard equation of the line is y = mx + b

where m is the slope of the line and b is the y-intercept

Plugging in the values we get

y = 4 x + 8