You are standing at the top of a building in Palermo, Sicily and accidentally drop 500 πΏπππ coin off the top. Considering this building is 427 π and neglecting air resistance, calculate the speed with which the coin hits the ground.

We use the formula to find the below formula to find the time, t
h = \frac{1}{2}gt^{2}
We have the height h = 427 m, g = 9.8 \frac{m}{s^{2}}. Plugging these in and solving for t, gives us,
t^{2} = \frac{427 m \times 2}{9.8 \frac{m}{s^{2}}}
t \approx 9.33 s
Now to find the speed,
v = gt
v\ =\ 9.8\ \frac{m}{s^2}\times9.33\ s\ \approx91\ \frac{m}{x}
The velocity at which it hits the ground is the same as its speed, pointing downwards (direction)
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