Qalaxia Knowlege Bot
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I found an answer from descanso.jpl.nasa.gov

Fundamentals of Electric Propulsion: Ion and Hall Thrusters


and specific impulse is somewhat less than that achievable in ion thrusters, but the thrust ... electrons emitted from the hollow cathode also leave the thruster with the ion ... is equal to the mass of the spacecraft, M, times its change in velocity, v: ... electrons between two plasmas or between a plasma and an electron emitter.


For more information, see Fundamentals of Electric Propulsion: Ion and Hall Thrusters

Qalaxia Master Bot
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I found an answer from www.jagranjosh.com

CBSE Class 12th Physics Notes: Dual Nature of Radiation and Matter


Jan 19, 2017 ... CBSE class 12 chapter wise notes based on chapter 11, Dual Nature of Radiation and Matter, of class 12 NCERT Physics textbook are available in ... Photoelectric Effect and Wave Theory of Light. Photon. Einstein's Photoelectric Equation: Energy Quantum of Radiation ... Kinetic Energy of Photoelectron.


For more information, see CBSE Class 12th Physics Notes: Dual Nature of Radiation and Matter

Veda
0

Given that

Potential difference V =. 500 V

Specific charge of electron \frac{e}{m} = 1.76*10^{11} C/kg

    

a)

Step 1: Get an expression for emitted electron speed

            Required formulas

                Kinetic energy K.E=\frac{1}{2}mv^2 .............................(1)

                  Where, m - mass and v - velocity  


                According to the conversion law

                          K.E = eV .............................(2)

                Where, charge of electron e=1.6*10^{-19} and V - potential difference(voltage)     

                

              From equation (1) and (2)

                       \frac{1}{2} mv^2 = eV

                       v = \sqrt{\frac{2eV}{m}}

                       v = \sqrt{2 V \frac{e}{m}} .............................(3)


Step 2:  Finding the speed of emitted electron

                  Plug in the given values in equation (3)

                        v = \sqrt{ 2 * 500 * 1.76*10^{11} }   

                        v = 1.327* 10^7 m/s


b)

Collector potential V = 10 M V = 10* 10^{6} V   

  

Step 1: Speed of emitted electron form collector

              Speed v = \sqrt{2 V \frac{e}{m}}             

                           v = \sqrt{2*10^7 * 1.76*10^{11}}

                           v = 1.88 * 10^{9} m/s


Step 2: Observation

              Speed of light c = 3* 10^{8} m/s  [/math]

              

             Speed of light less the speed of electron ( v > c) which is not possible practically since noting can travel faster than

              speed of light.

          

            The relativistic mass is given as follows

                Modified mass m=m_0*(1-\frac{v^2}{c^2})^{-\frac{1}{2}}

                   m_o - mass of particle at rest position