\sin(x)= - 0.9. What is \cos(90\degree - x)?

Anonymous
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Step 1: Recall the complimentary angles relation.
THEOREM: If \angle A \text{ and } \angle B are the acute angles of a right triangle,
sin A = cos B
EXAMPLE: 90°–x and x are complementary, since their angles sum to 90°.
So, the cosine of 90°–x is equal to the sine of x.
\cos(90 - x) = \sin(x) = -0.9